After spending five seasons with the Cleveland Indians outfielder Al Luplow was sold to the New York Mets on November 29, 1965. He made his Met debut on April 16, 1966 against the Atlanta Braves as a defensive replacement; he replaced Dick Stuart and finished out the game in leftfield. He would spend the first couple of months of the 1966 season serving primarily as a pinch hitter before becoming a mainstay in the Met outfield in June.
Luplow appeared in 111 games for the Mets in 1966, playing all three outfield positions, and hit a respectable .251 with 7 home runs and 31 RBIs. The highlight of his season came on September 17 when he hit 2 home runs and drove in 3 runs against the San Francisco Giants. Unfortunately, his heroics were not enough as the Mets lost the game 6-4.
Al Luplow returned to the Mets for the 1967 season but struggled at the plate and with his average at just .205 was sold to the Pittsburgh Pirates on June 21, 1967. He finished out the season with the Pirates before retiring.
In two seasons with the Mets Luplow appeared in 152 games and batted .240 with 10 home runs and 40 RBIs.
While with the Mets Luplow wore number 18.
Al Luplow also played for the Cleveland Indians from 1961-1965 and the Pittsburgh Pirates in 1967.